Solve the following pair of equations by cross - multiplication method.
2ax + 3by = a + 2b
3ax + 2by = 2a + b
2ax + 3by = a + 2b
3ax + 2by = 2a + b
Given, pair of equations is
2ax + 3by = a + 2b ⇒ 2ax + 3by –(a + 2b) = 0
3ax + 2by = 2a + b ⇒ 3ax + 2by –(2a + b) = 0
By cross - multiplication method, we have


![]()

On taking I and III ratio, we get
![]()
![]()
![]()
On taking II and III ratio, we get
![]()
![]()
![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.


