A fraction becomes 1/3 when 1 is subtracted from the numerator and it becomes 1/4 when 8 is added to its denominator. Find the fraction.
Let the numerator = x
and the denominator = y
So, the fraction ![]()
According to the question,
Condition I:
![]()
⇒ 3(x – 1) = y
⇒ 3x – 3 = y
⇒ 3x – y – 3 = 0 …(i)
Condition II:
![]()
⇒ 4x = y + 8
⇒ 4x – y = 8
⇒ 4x – y – 8 = 0 …(ii)
By cross - multiplication method, we have

![]()

On taking I and III ratio, we get
![]()
⇒ x = 5
On taking II and III ratio, we get
![]()
⇒ y = 12
So, the numerator is 5 and the denominator is 12
Hence, the fraction is ![]()
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