The sum of the numerator and denominator of a fraction is 4 more than twice the numerator. If the numerator and denominator are increased by 3, then are in the ratio 2 : 3. Determine the fraction.
Let the numerator = x
and the denominator = y
So, the fraction ![]()
According to the question,
Condition I:
x + y = 2x + 4
⇒ x + y – 2x = 4
⇒ – x + y = 4
⇒ y = 4 + x …(i)
Condition II:
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⇒ 3(x + 3) = 2( y + 3)
⇒ 3x + 9 = 2y + 6
⇒ 3x – 2y = – 3 …(ii)
On putting the value of y in Eq.(ii) , we get
3x – 2(4 + x) = – 3
⇒ 3x – 8 – 2x = – 3
⇒ x = 5
On putting the value of x in Eq. (i), we get
y = 4 + 5
⇒ y = 9
So, the numerator is 5 and the denominator is 9
Hence, the fraction is ![]()
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