The numerator of a fraction is one less than its denominator. If 3 is added to each of the numerator and denominator, the fraction is increased by 3/28, find the fraction. 28
Let the denominator = x
Given that numerator is one less than the denominator
⇒ numerator = x – 1
So, the fraction ![]()
According to the question,
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⇒ 28{(x2 + 2x) – (x2 –x + 3x – 3)} = 3 (x2 + 3x)
⇒ 28x2 + 56x – 28x2 – 56x + 84 = 3x2 + 9x
⇒ 3x2 + 9x – 84 = 0
⇒ x2 + 3x – 28 = 0
⇒ x2 + 7x – 4x – 28 = 0
⇒ x(x + 7) – 4(x + 7) = 0
⇒ (x – 4) (x + 7) = 0
⇒ x = 4 and – 7
But x is a natural number
Hence, x = 4
So, the fraction is ![]()
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