Q14 of 186 Page 4

Taxi charges in a city consist of fixed charges per day and the remaining depending upon the distance travelled in kilometers. If a person travels 110 km, he pays Rs. 690, and for travelling 200 km, he pays Rs. 1050. Find the fixed charges per day and the rate per km.

Let fixed charge = Rs. x

and charge per kilometer = Rs. y


According to the question,


x + 110y = 690 …(i)


and x + 200y = 1050 …(ii)


On subtracting Eq. (i) from Eq. (ii), we get


x + 200y – x – 110y = 1050 – 690


⇒ 90y = 360


⇒ y = 40


On putting the value of y = 40 in Eq. (i), we get


x + 110(40) = 690


⇒ x + 440 = 690


⇒ x = 690 – 440 = 250


Hence, monthly fixed charges is Rs. 250 and charge per kilometer is Rs. 40


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