A man travels 370 km, partly by train and partly by car. If he covers 250 km by train and the rest by car, it takes him 4 hours. But, if he travels 130 km by train and the rest by car, he takes 18 minutes longer. Find the speed of the train and that of the car.
Let the speed of a train = x km/hr
And the speed of a car = y km/hr
Total distance travelled = 370km
According to the question,
If he covers 250km by train and rest by car i.e. (370 – 250) = 120km
Time take = 4hrs
If he travels 130km by train and rest by car i.e. (370 – 130) = 240km
He takes 18min longer i.e. ![]()
So, total time = train time + car time
We know that,
![]()
…(i)
…(ii)
![]()
250u + 120v = 4 …(iii)
and 130u + 240v = 4.3 …(iv)
On multiplying Eq. (iii) by 2
500u + 240v = 8 …(v)
On subtracting Eq. (iv) from Eq. (v), we get
500u + 240v – 130u – 240v = 8 – 4.3
⇒ 370u = 3.7
![]()
![]()
On putting the value of v in Eq. (iv), we get
![]()
⇒ 1.3 + 240v = 4.3
⇒ 240v = 3
![]()
So, we get
and ![]()
⇒ x = 100 and y = 80
Hence, the speed of the train is 100km/hr and the speed of the car is 80km/hr.
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