Q29 of 186 Page 4

The age of the father is 3 years more than 3 times the son's age. 3 years here, the age of the father will be 10 years more than twice the age of the son. Find their present ages.

Let the age of father = x years

And the age of his son = y years


According to the question,


x = 3 + 3y ...(i)


Three year here,


Father’s age = (x + 3) years


Son’s age = (y + 3) years


According to the question,


(x + 3) = 10 + 2(y + 3)


⇒ x + 3 = 10 + 2y + 6


⇒ x = 2y + 13 …(ii)


From Eq. (i) and (ii), we get


3 + 3y = 13 + 2y


⇒ 3y – 2y = 13 – 3


⇒ y = 10


On putting the value of y = 7 in Eq. (i), we get


x = 3 + 3(10)


⇒ x = 3 + 30


⇒ x = 33


Hence, the age of father is 33 years and the age of his son is 10 years.


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