Q9 of 186 Page 4

Two numbers differ by 4 and their product is 192. Find the numbers.

Let the two numbers be x and y.

According to the question,


x – y = 4 …(i)


Also, x×y = 192


…(ii)


On putting the value of in Eq. (i), we get



⇒ 192 – y2 = 4y


⇒ y2 + 4y – 192 = 0


⇒ y2 + 16y – 12y – 192 = 0


⇒ y(y + 16) – 12(y + 16) = 0


⇒ (y – 12)(y + 16) = 0


⇒ y = – 16 and 12


But y = – 16 can’t be the one number as it is given that the numbers are positive.



Hence, the two numbers are 16 and 12.


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