Solve for x and y the following system of equations:

Where (2x + 3y) ≠ 0 and (3x – 2y) ≠ 0

Given pair of linear equations is

…(i)

And …(ii)

On multiplying Eq. (i) by 7 and Eq. (ii) by to make the coefficients equal of first term, we get the equation as

…(iii)

…(iv)

On substracting Eq. (iii) from Eq. (iv), we get

…(a)

On multiplying Eq. (ii) by to make the coefficients equal of second term, we get the equation as

…(v)

On substracting Eq. (i) from Eq. (iv), we get

…(b)

From Eq. (a) and (b), we get

⇒ 2(4 + 2y) = 3(7 – 3y)

⇒ 8 + 4y = 21 – 9y

⇒ 4y + 9y = 21 – 8

⇒ 13y = 13

⇒ y = 1

On putting the value of y = 1 in Eq. (b), we get

Hence, x = 2 and y = 1 , which is the required solution.