Solve for x and y the following system of equations:

Given pair of linear equations is

…(i)

And …(ii)

On multiplying Eq. (i) by 4 and Eq. (ii) by 3 to make the coefficients equal of second term, we get the equation as

…(iii)

…(iv)

On substracting Eq. (iii) from Eq. (iv), we get

⇒ x + y = 11 …(a)

On putting the value of x + y = 11 in Eq. (1), we get

⇒ 6(x – y) = 30

⇒ x – y = 5 …(b)

Adding Eq. (a) and (b), we get

⇒ 2x = 16

⇒ x = 8

On putting value of x = 8 in eq. (a), we get

8 + y = 11

⇒ y = 3

Hence, x = 8 and y = 3 , which is the required solution.