A plane left 30 minutes later than the scheduled time and in order to reach the destination 1500 km away in time, it has to increase the speed by 250 km/hr from the usual speed. Find its usual speed.
Let the usual time taken by the aeroplane = x km/hr
Distance to the destination = 1500km
We know that,
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Hence, speed ![]()
According to the question,
Plane left 30min later than the scheduled time
30min ![]()
Time taken by the aeroplane ![]()
∴ the speed of the plane ![]()
Given that speed has to increase by 250 km/hr


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⇒ 6(2x – 2x + 1) = 2x2 – x
⇒ 6 = 2x2 – x
⇒ 2x2 –x – 6 = 0
⇒ 2x2 – 4x + 3x – 6 = 0
⇒ 2x (x – 2) + 3 (x – 2) = 0
⇒ (2x + 3) (x – 2) = 0
⇒ (2x + 3) = 0 or (x – 2) = 0
∴
or x = 2
Since, time can’t be negative.
Hence, the time taken by the aeroplane is 2hrs and the speed is 750km/hr
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