Q1 of 186 Page 4

Solve the following system of equations by elimination method:

2x + 5y = 1


2x + 3y = 3

Given pair of linear equations is


2x + 5y = 1 …(i)


And 2x + 3y = 3 …(ii)


On subtracting Eq. (ii) from Eq. (i), we get


2x + 3y – 2x – 5y = 3 – 1


⇒ – 2y = 2


⇒ y = – 1


On putting y = – 1 in Eq. (ii), we get


2x + 3( – 1) = 3


⇒ 2x – 3 = 3


⇒ 2x = 6


⇒ x = 6/2


⇒ x = 3


Hence, x = 3 and y = – 1 , which is the required solution.


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