The sum of the numerator and denominator of a fraction is 8. If 3 is added to both 3 the numerator and the denominator, the fraction becomes 3/4. Find the fraction.
Let the numerator = x
and the denominator = y
So, the fraction ![]()
According to the question,
Condition I:
x + y = 8
⇒ y = 8 – x …(i)
Condition II:
![]()
⇒ 4(x + 3) = 3( y + 3)
⇒ 4x + 12 = 3y + 9
⇒ 4x – 3y = – 3 …(ii)
On putting the value of y in Eq.(ii) , we get
4x – 3(8 – x) = – 3
⇒ 4x – 24 + 3x = – 3
⇒ 7x = 21
⇒ x = 3
On putting the value of x in Eq. (i), we get
y = 8 – 3
⇒ y = 5
So, the numerator is 3 and the denominator is 5
Hence, the fraction is ![]()
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