Solve for x and y the following system of equations:

Given pair of linear equations is

…(i)

And …(ii)

On multiplying Eq. (i) by 3 and Eq. (ii) by 2 to make the coefficients equal of first term, we get the equation as

…(iii)

…(iv)

On substracting Eq. (iii) from Eq. (iv), we get

⇒ y + 1 = 3

⇒ y = 3 – 1

⇒ y = 2

On putting the value of y = 2 in Eq. (ii), we get

⇒ x – 1 = 2

⇒ x = 3

Hence, x = 3 and y = 2 , which is the required solution.