The path of highway number 1 and 2 are given by the equations x — y = 1 and 2x + 3y = 12 respectively. Represent these equations geometrically.
The given equation is
x – y = 1
and
2x + 3y = 12
Now, let us find atleast two solutions of each of the above equations, as shown in the following tables.
Table for x – y = 1 or y = x – 1

Now, table for 2x + 3y = 12![]()


From the graph, it is clear that lines represented by the equations x – y = 1 and 2x + 3y – 12 = 0 are intersecting at a point A i.e. (3,2)
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