Find the indicated terms in each of the following arithmetic progression:
a = 3, d = 2; ; tn, t10
Given: a = 3 , d = 2
To find: tn and t10
We have,
tn = a + (n – 1)d
tn = 3 + (n – 1) 2
= 3 + 2n – 2
tn = 2n + 1
Now, n = 10
So, t10 = 3 + (10 – 1)2
= 3 + 9×2
t10 = 3 +18
t10 = 21
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