If 10 times the 10th term of an A.P. is equal to 15 times the 15th term, show that its 25th term is zero.
Given: 10 × a10 = 15 × a15
To Prove: a25 = 0
Now,
10 × (a + 9d) = 15 × (a + 14d)
⇒ 10a + 90d = 15a + 210d
⇒ 10a – 15a = 210d – 90d
⇒ –5a = 120d
⇒ a = –24d …(i)
Now,
an = a + (n – 1)d
a25 = –24d + (25 – 1)d [from (i)]
a25 = –24d + 24d
a25 = 0
Hence Proved
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