Find the number of terms of the A.P.
41, 38, 35, ..., 8?
Here, a = 41 , d = 38 – 41 = –3 and l = 8
where l = a + (n – 1)d
⇒ 8 = 41 + (n – 1)(–3)
⇒ 8 = 41 –3n + 3
⇒ 8 = 44 – 3n
⇒ 8 – 44 = –3n
⇒ –36 = –3n
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Hence, the number of terms in the given AP is 12
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