Q10 of 176 Page 8

Find the first negative term of sequence 999, 995, 991, 987, ...

AP = 999, 995, 991, 987,…


Here, a = 999, d = 995 – 999 = –4


an < 0


a + (n – 1)d < 0


999 + (n – 1)(–4) < 0


999 – 4n + 4 < 0


1003 – 4n < 0


1003 < 4n



n > 250.75


Nearest term greater than 250.75 is 251


So, 251st term is the first negative term


Now, we will find the 251st term


an = a +(n – 1)d


a251 = 999 + (251 – 1)(–4)


a251 = 999 + 250 × –4


a251 = 999 – 1000


a251 = – 1


, –1 is the first negative term of the given AP.


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