If tn be the nth term of an A.P. such that
find
.
Given: ![]()
To find: ![]()
We know that,
tn = a + (n – 1)d
So,
![]()
![]()
⇒ 3(a+3d) = 2(a+6d)
⇒ 3a + 9d = 2a + 12d
⇒ 3a – 2a = 12d – 9d
⇒ a = 3d …(i)
Now,
[from (i)]
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