If a2, b2, c2 are in A.P., show that are in A.P.

a2, b2, c2 are in AP∴ b2 – a2 = c2 – b2⇒(b – a)(b + a) = (c – b)(c + b)Hence Proved

Q6 of 176 Page 8

If a², b², c² are in A.P., show that are in A.P.

a², b², c² are in AP

∴ b² – a² = c² – b²

⇒(b – a)(b + a) = (c – b)(c + b)

Hence Proved

Sum of three numbers in A.P. is 3 and their product is — 35. Find the numbers.

If are in A.P. and a + b + c ≠ 0, prove that are in A.P.

If a, b, c are in A.P., prove that

are in A.P.

If a, b, c are in A.P., prove that

(b + c)² — a², (c + a)² — b², (a + b)² — c² are in A.P.