Which term of A.P. 3, 8, 13, 18, ... is 88?
Here, a = 3, d = 8 – 3 = 5 and an = 88
To find : n
We have,
an = a + (n – 1)d
⇒ 88 = 3 + (n – 1) × (5)
⇒ 88 = 3 + 5n – 5
⇒ 88 = –2 + 5n
⇒88 + 2 = 5n
⇒ 90 = 5n
⇒ n = 18
Therefore, the 18th term of the given AP is 88.
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