Which term of the A.P. 5, 9, 13, 17, ... is 81?
Here, a = 5, d = 9 – 5 = 4 and an = 81
To find : n
We have,
an = a + (n – 1)d
⇒ 81 = 5 + (n – 1) × 4
⇒ 81 = 5 + 4n – 4
⇒ 81 = 4n + 1
⇒ 80 = 4n
⇒ n = 20
Therefore, the 20th term of the given AP is 81.
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