For the following A.P's write the first term and common difference:
147, 148, 149, 150, ...
In general, for an AP a1, a2, . . . .,an, we have
d = ak+1 - ak
where ak+1 and ak are the (k+1)th and kth terms respectively.
For the list of numbers: 147, 148, 149, 150, ...
a2 – a1 = 148 – 147 = 1
a3 – a2 = 149 – 148 = 1
a4 – a3 = 150 – 149 = 1
Here, the difference of any two consecutive terms in each case is -1. So, the given list is an AP whose first term a is 147 and common difference d is 1.
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