Q5 of 176 Page 9

For the following A.P's write the first term and common difference:

147, 148, 149, 150, ...

In general, for an AP a1, a2, . . . .,an, we have


d = ak+1 - ak


where ak+1 and ak are the (k+1)th and kth terms respectively.


For the list of numbers: 147, 148, 149, 150, ...


a2 – a1 = 148 – 147 = 1


a3 – a2 = 149 – 148 = 1


a4 – a3 = 150 – 149 = 1


Here, the difference of any two consecutive terms in each case is -1. So, the given list is an AP whose first term a is 147 and common difference d is 1.


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