If the sum of n terms of an A.P. is nP + 1/2 n( n —1)Q , where P and Q are constants, find the common difference of the A.P.
![]()
Taking n = 1, we get
![]()
⇒ S1 = P
⇒ a1 = P
Taking n = 2, we get
![]()
⇒ S2 = 2P + Q
∴ a2 = S2 – S1 = 2P + Q – P = P + Q
Taking n = 3, we get
![]()
⇒ S3 = 3P + 3Q
∴ a3 = S3 – S2 = 3P + 3Q – 2P – Q = P + 2Q
So, a = P,
d = a2 – a1 = P + Q – (P) = Q
= a3 – a2 = P + 2Q – (P + Q) = P + 2Q – P – Q = Q
Hence, the common difference is Q.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.