A sum of money kept in a hank amounts to Rs. 600/– in 4 years and Rs. 800/– in 12 years. Find the sum and interest carried every year.
Let the required sum = a
and the interest carried every year = d
According to question,
In 4years, a sum of money kept in bank account = Rs. 600
i.e. t5 = 600 ⇒ a + 4d = 600 …(i)
and in 12 years , sum of money kept = Rs. 800
i.e. t13 = 800 ⇒ a + 12d = 800 …(ii)
Solving linear equations (i) and (ii), we get
a + 4d – a – 12d = 600 – 800
⇒ – 8d = –200
⇒ d = 25
Putting the value of d in eq.(i), we get
a + 4(25) = 600
⇒ a + 100 = 600
⇒ a = 500
Hence, the sum and interest carried every year is Rs 500 and Rs 25 respectively.
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