For the following A.P's write the first term and common difference:
6, 3, 0, - 3, ...
In general, for an AP a1, a2, . . . .,an, we have
d = ak+1 - ak
where ak+1 and ak are the (k+1)th and kth terms respectively.
For the list of numbers: 6, 3, 0, -3, . . .
a2 – a1 = 3 – 6 = -3
a3 – a2 = 0 – 3 = -3
a4 – a3 =-3 – 0 = -3
Here, the difference of any two consecutive terms in each case is -3.
So, the given list is an AP whose first term a is 6, and common difference d is -3.
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