In the following A.P., find the missing terms:
□, □, 13, □, □, 22
Given: a3 = 13 and a6 = 22
We know that,
an = a + (n – 1)d
a3 = a + (3 – 1)d
13 = a + 2d …(i)
and a6 = a +(6 – 1)d
22 = a + 5d …(ii)
Solving linear equations (i) and (ii), we get
a + 2d – a – 5d = 13 – 22
⇒ –3d = 9
⇒ d = 3
Putting the value of d in eq. (i), we get
a + 2(3) = 13
⇒ a + 6 = 13
⇒ a = 7
Now, a2 = a + d = 7 + 3 = 10
a4 = a + 3d = 7 + 3(3) = 7 + 9 = 16
a5 = a + 4d = 7 + 4(3) = 7 + 12 = 19
Hence, the missing terms are 7, 10, 16 and 19
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