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8. Arithmetic Progressions (AP)
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Q18 of 176 Page 8

In the following A.P., find the missing terms:

– 4, □,□,□,□, 6

Here, a = –4, n = 6 and l = 6


We have,


l = a + (n – 1)d


⇒6 = –4 + (6 – 1)d


⇒6 = –4 + 5d


⇒10 = 5d



So, the missing terms are –


a2 = a + d = –4 + 2 = –2


a3 = a + 2d = –4 + 2(2) = –4 + 4 = 0


a4 = a + 3d = –4 + 3(2) = –4 + 6 = 2


a5 = a + 4d = –4 + 4(2) = –4 + 8 = 4


Hence, the missing terms are –2, 0, 2 and 4


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Questions · 176
8. Arithmetic Progressions (AP)
1 1 1 1 1 1 2 2 2 2 3 3 4 4 4 4 4 4 4 4 5 5 5 5 5 5 5 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 7 7 7 7 7 7 7 1 1 1 1 2 3 4 5 5 6 7 7 7 7 7 8 8 9 9 9 10 11 12 13 14 15 16 17 17 17 17 18 18 18 18 18 18 18 18 18 19 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 1 2 3 3 4 4 5 6 7 7 7 8 9 10 10 10 1 2 3 3 4 5 6 7 7 8 9 10 11 12 13 14 15 15 16 17 18 19 20 20 21 22 23 24 24 25 26 27 28 29 30 31 32 33 34 34 35 36 37 38 39 40 41 42 43 44 44 45 46 47 48
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