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8. Arithmetic Progressions (AP)
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Q9 of 176 Page 8

Find the number of terms of the A.P.

7, 11, 15, ..., 139?

Here, a = 7 , d = 11 – 7 = 4 and l = 139


where l = a + (n – 1)d


⇒ 139 = 7 + (n – 1)(4)


⇒ 139 = 7 + 4n – 4


⇒ 139 = 3 + 4n


⇒ 139 – 3 = 4n


⇒ 136 = 4n



Hence, the number of terms in the given AP is 34


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Questions · 176
8. Arithmetic Progressions (AP)
1 1 1 1 1 1 2 2 2 2 3 3 4 4 4 4 4 4 4 4 5 5 5 5 5 5 5 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 7 7 7 7 7 7 7 1 1 1 1 2 3 4 5 5 6 7 7 7 7 7 8 8 9 9 9 10 11 12 13 14 15 16 17 17 17 17 18 18 18 18 18 18 18 18 18 19 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 1 2 3 3 4 4 5 6 7 7 7 8 9 10 10 10 1 2 3 3 4 5 6 7 7 8 9 10 11 12 13 14 15 15 16 17 18 19 20 20 21 22 23 24 24 25 26 27 28 29 30 31 32 33 34 34 35 36 37 38 39 40 41 42 43 44 44 45 46 47 48
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