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8. Arithmetic Progressions (AP)
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Q15 of 176 Page 8

Solve for x

1 + 6+11 + 16 +...+x= 148

Here, a = 1, d = 6 – 1 = 5 and Sn = 148






⇒ 296 = n[5n – 3]


⇒ 5n2 – 3n – 296 = 0


⇒ 5n2 – 40n + 37n – 296 = 0


⇒ 5n(n – 8) + 37(n – 8) = 0


⇒ (5n + 37)(n – 8) = 0


⇒ 5n + 37 = 0 or n – 8 = 0


⇒ or n = 8


But is not a positive integer.


∴ n = 8


⇒ x = a8 = a + 7d = 1 + 7 × 5 = 1 + 35 = 36


Hence, x = 36


More from this chapter

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13

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14

Which term of the A.P. 4, 9, 14, ... is 89? Also, find the sum 4 + 9 + 14 + + 89.

15

Solve for x

25+22+19+ 16+...+x= 115

16

Find the number of terms of the A.P. 64, 60, 56, ... so that their sum is 544. Explain the double answer.

Questions · 176
8. Arithmetic Progressions (AP)
1 1 1 1 1 1 2 2 2 2 3 3 4 4 4 4 4 4 4 4 5 5 5 5 5 5 5 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 7 7 7 7 7 7 7 1 1 1 1 2 3 4 5 5 6 7 7 7 7 7 8 8 9 9 9 10 11 12 13 14 15 16 17 17 17 17 18 18 18 18 18 18 18 18 18 19 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 1 2 3 3 4 4 5 6 7 7 7 8 9 10 10 10 1 2 3 3 4 5 6 7 7 8 9 10 11 12 13 14 15 15 16 17 18 19 20 20 21 22 23 24 24 25 26 27 28 29 30 31 32 33 34 34 35 36 37 38 39 40 41 42 43 44 44 45 46 47 48
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