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8. Trigonometric Identities
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Q11 of 186 Page 343

If (sin θ + cos θ) = √2 cos θ, show that cot θ = (√2 + 1).

Given: (sin θ + cos θ) = √2 cos θ

Divide both sides by sin θ:


(sin θ + cos θ)/sin θ = √2 cos θ/sin θ


⇒ 1 + cot θ = √2 cot θ


⇒ (√2 – 1)cot θ = 1


⇒ cot θ =


⇒ cot θ =


⇒ cot θ =


⇒ cot θ = √2 + 1


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Questions · 186
8. Trigonometric Identities
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