Consider sin2 θ + = (sin2θ) + (1/sec2 θ)(∵ 1 + tan2 θ = sec2 θ)= (sin2θ) + (cos2θ)(∵ sin2 θ + cos2 θ = 1)= 1

Q5 of 186 Page 345

Write the value of .

Consider sin² θ +

= (sin²θ) + (1/sec² θ)

(∵ 1 + tan² θ = sec² θ)

= (sin²θ) + (cos²θ)

(∵ sin² θ + cos² θ = 1)

= 1

Write the value of (1 + tan²θ) cos² θ.

Write the value of (1 + cot²θ) sin² θ.

Write the value of .

Write the value of sin θ cos (90° – θ) + cos θ sin (90° – θ).