Q25 of 186 Page 345

If cos B = 3/5 and (A + B) = 90°, find the value of sin A.

We are given that: cos B = 3/5

⇒ sin (90° – B) = 3/5

Since A + B = 90°, therefore A = 90° – B

Therefore, sin (90° – B) = sin A = 3/5

If tan θ = 1/√5write the value of

If cot A = 4/3 and (A + B) = 90°, what is the value of tan B?

If √3sin θ = cos θ and θ is an acute angle, find the value of θ.

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