Q39 of 186 Page 350

If 2x = sec A and 2/x = tan A then

Given: 2x = sec A, and 2/x = tan A

Consider 2(x² – (1/ x²))

= (1/2) [sec² A – tan² A]

= (1/2)[1]

= 1/2 (∵ sec² x – tan² x = 1)

If cos θ = 4/5 then tan θ = ?

If 3x = cosec θ and 3/x = cot θ, then

If tan θ = 4/3, then (sin θ + cos θ) = ?

If (tan θ + cot θ) = 5 then (tan² θ + cot² θ) = ?