Consider 4 tan2 θ – = 4 tan2 θ – 4 sec2 θ= 4(tan2 θ – sec2 θ)= 4( – 1) (∵1 + tan2 θ = sec2 θ)= – 4

Q14 of 186 Page 345

Write the value of .

Consider 4 tan² θ – = 4 tan² θ – 4 sec² θ

= 4(tan² θ – sec² θ)

= 4( – 1) (∵1 + tan² θ = sec² θ)

= – 4

Write the value of (1 + tan² θ)(1 + sin θ)(1 – sin θ).

Write the value of 3 cot² θ – 3 cosec² θ.

Write the value of

If sin θ = 1/2, write the value of (3 cot² θ + 3).