Q24 of 186 Page 350

If x tan 45° cos 60° = sin 60° cot 60° then x = ?

Given: x tan 45° cos 60° = sin 60° cot 60°

⇒ x × 1 × (1/2) = (√3/2) × (1/√3)

⇒ x/2 = 1/2

⇒ x = 1

If √3tan 2θ – 3 = 0 then θ = ?

If tan x = 3 cot x then x = ?

If tan²45° – cos²30° = x sin 45° cos 45° then x = ?

sec²60° – 1 = ?