Q41 of 186 Page 350

If (tan θ + cot θ) = 5 then (tan2 θ + cot2 θ) = ?

Given: tan θ + cot θ = 5


Squaring both sides, we get:


tan2 θ + cot2 θ + 2 tan θ cot θ = 25


tan2 θ + cot2 θ = 25 – 2 tan θ cot θ


= 25 – 2


= 23

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