Given: tan θ = 1/√7∴ tan2 θ = 1/7Consider = Multiply numerator and denominator by sin θ:= = = 6/8= 3/4

Q43 of 186 Page 350

If

Given: tan θ = 1/√7

∴ tan² θ = 1/7

Consider =

Multiply numerator and denominator by sin θ:

= 6/8

= 3/4

If (tan θ + cot θ) = 5 then (tan² θ + cot² θ) = ?

If (cos θ + sec θ) = 5/2, then (cos² θ + sec² θ) = ?