If √3 tan θ = 3 sin θ, prove that (sin2 θ – cos2 θ) = 1/3.
Given: √3 tanθ = 3 sinθ
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Also, we know, ![]()
⇒ ![]()
⇒ ![]()
Now, we need to prove that:
sin2θ – cos2θ = 1/3
⇒ L.H.S = 
⇒ L.H.S = ![]()
⇒ L.H.S = 1/3
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