If sin θ = 1/2, write the value of (3 cot2 θ + 3).

Give: sin θ = 1/2Therefore cosec θ = 1/sin θ= 2Consider 3 cot2 θ + 3 = 3 (cot2 θ + 1)= 3 cosec2 θ (∵ 1 + cot2 θ = cosec2 θ)= 3 (2)2= 3 × 4= 12

Q16 of 186 Page 345

If sin θ = 1/2, write the value of (3 cot² θ + 3).

Give: sin θ = 1/2

Therefore cosec θ = 1/sin θ

= 2

Consider 3 cot² θ + 3 = 3 (cot² θ + 1)

= 3 cosec² θ (∵ 1 + cot² θ = cosec² θ)

= 3 (2)²

= 3 × 4

= 12

Write the value of .

Write the value of

If cos θ = 2/3, write the value of (4 +4 tan² θ).

If cos θ = 7/25, write the value of (tan θ + cot θ).