Q32 of 186 Page 350

If tan θ = 8/15, then cosec θ = ?

Given: tan θ = 8/15 = Perpendicular/Base


On comparing, we get:


Perpendicular = 8


Base = 15


Therefore, (Hypotenuse)2 = (Perpendicular)2 + (Base)2


= 64 + 225


= 289


Therefore, hypotenuse = √289


= 17


Therefore cosec θ = Hypotenuse/Perpendicular


= 17/8

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