If x = a sin θ and y = b cos θ, write the value of (b2x2 + a2y2).

Given: x = a sin θy = b cos θThen b2x2 + a2y2 = b2(a sin θ)2 + a2(b cos θ)2= a2b2 sin2 θ + a2 b2 cos2 θ= a2b2 (sin2 θ + cos2 θ)= (a2b2) × 1= a2b2

Q34 of 186 Page 345

If x = a sin θ and y = b cos θ, write the value of (b²x² + a²y²).

Given: x = a sin θ

y = b cos θ

Then b²x² + a²y² = b²(a sin θ)² + a²(b cos θ)²

= a²b² sin² θ + a² b² cos² θ

= a²b² (sin² θ + cos² θ)

= (a²b²) × 1

= a²b²

Find the value of .

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