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8. Trigonometric Identities
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Q20 of 186 Page 359

If sec 5A = cosec (A – 36°) and 5A is an acute angle, show that A = 21°.

We are given that: sec 5A = cosec (A – 36°)

∴We can rewrite it as: cosec (90° – 5A) = cosec (A – 36°)


On comparing both sides, we get,


90° – 5A = A – 36°


⇒ A + 5A = 90° + 36°


⇒ 6A = 126°


⇒ A = 21°


Hence, proved.


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Questions · 186
8. Trigonometric Identities
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