Prove that
.
Consider L.H.S. = ![]()
Multiply and divide the first term by (sec θ + tan θ):
= ![]()
=
– sec θ
= sec θ + tan θ – sec θ (∵1 + tan2 θ = sec2 θ)
= tan θ
Consider R.H.S. = ![]()
Multiply and divide the second term by (sec θ – tan θ):
= ![]()
= sec θ – ![]()
= sec θ – sec θ + tan θ (∵1 + tan2 θ = sec2 θ)
= tan θ
Therefore, L.H.S. = R.H.S.
Hence, proved.
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