Q34 of 186 Page 350

If tan θ = √3, then sec θ = ?

Given: tan θ = √3 = Perpendicular/Base


On comparing, we get:


Perpendicular = √3


Base = 1


Therefore, (Hypotenuse)2 = (Perpendicular)2 + (Base)2


= 3 + 1


= 4


Therefore, hypotenuse = √4


= 2


Therefore sec θ = Hypotenuse/Base


= 2/1 = 2

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