Q35 of 186 Page 350

If sec θ = 25/7, then sin θ = ?

Given: sec θ = 25/7


Therefore, cos θ = 1/sec θ = 7/25 = Base/Hypotenuse


Therefore, on comparing, Base = 7 and Hypotenuse = 25


In a right – angled triangle, (Hypotenuse)2 = (Perpendicular)2 + (Base)2


625 = (Perpendicular)2 + 49


Therefore, Perpendicular = √(625 – 49) = √(576)


= 24


Therefore sin θ = Perpendicular/Hypotenuse


= 24/25

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