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8. Trigonometric Identities
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Q3 of 186 Page 350

tan 10° tan 15° tan 75° tan 80° = ?

Consider tan 10° tan 15° tan 75° tan 80°


= tan 10° tan 80° tan 15° tan 75°


= tan 10° tan (90 – 10)° tan 15° tan (90 – 15)°


= (tan 10° cot 10°) (tan 15° cot 15°)


= (1) × (1) = 1

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tan 5° tan 25° tan 30° tan 65° tan 85° = ?

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cos 1° cos 2° cos 3° ... cos 180° = ?

Questions · 186
8. Trigonometric Identities
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