Q38 of 186 Page 350

If 3x = cosec θ and 3/x = cot θ, then

Given: 3x = cosec θ , and 3/x = cot θ


Consider 3(x2 – (1/ x2)) =



=


= (1/3)(cosec2 θ – cot2 θ)


= 1/3 (∵ cosec2 x – cot2 x = 1)

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