Q4 of 186 Page 359

If sin θ = √3/2, then (cosec θ + cot θ) = ?

Given: sin θ = √3/2

Therefore, cosec θ = 1/sin θ = 2/√3

cos θ = √(1 – sin² θ)

= √(1 – (3/4))

= √(1/4)

= 1/2

cot θ = cos θ/sin θ = (1/2)/√3/2

= 1/√3

Therefore, (cosec θ + cot θ) = (2/√3) + (1/√3)

= 3/√3

= √3

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